File photo of Mumbai Indians.© Bcci
Harbhajan Singh has classified his former side, Mumbai Indians as “Team to Beat” and predicted that the five -time champions will end in the top two of the group standing in the 18th edition of the Indian Premier League (IPL). The Indians of Mumbai, who are known for their customary slow style and then going to the end of the group’s phase, have been re-done. On Thursday, MI ensured that Rajasthan Royals dropped their target attempts down from the drain as they had sealed their sixth win over the trot to go to the top of the table.
MI found his lost collection and continued singing in harmony, as he has done on several occasions in the past. Mumbai’s winning lineage was for the show on Thursday, as he provoked Rajasthan Royals with a win of 100 runs in the scorching summer of Jaipur.
Rohit Sharma and Ryan are going to Burcek with Bat with Ryon Ricelton, while Jasprit Bumrah and Trent Bowlt Balling to harass the opposition batsmen with their tough pace, Harbhai saw Mumbai finishing in the top two.
“Total dominance from MI. They are a champion team playing like a champion team. It will be difficult for any team to catch them. Out of 11 players, nine or 10 can win the game singlesly. There is a team to defeat MI. I believe they will finish in the top two places. They can finish anywhere with 18 or 20 points,” Harbhajan said on his Yachitage. “
The success story of MI began with Rohit and Ricelton, who was blazing all the guns to raise a stand of 116 runs in 11.5 overs. Suryakumar Yadav and Hardik Pandya added the Rajasthan’s bowling attack to the cake with a cruel attack and MI up to 217/2.
In response, Bault, Bumrah, and experienced ball Twicker Karn Sharma wreaked havoc with the ball to get Rajasthan out of their grief and showed them the way to get out of the race for the playoffs.
(Except for the headline, the story has not been edited by NDTV employees and is published by a syndicated feed.)
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